Question

A train accelerates uniformly from 36km/h to 72km/h in 10 seconds. Its acceleration is​

Answer 1

Step-by-step explanation:

Initial Velocity (u) = 36 km/h = 10 m/s. Final Velocity (v) = 72 km/h = 20 m/s.

Answer 2

✪ Given :-

• Initial velocity = 36 Km/h
• Final velocity = 72 Km/h
• Time taken = 10 sec

------------------------------------------------------------

✪ To Find :-

• Acceleration of the train

------------------------------------------------------------

✪ Solution :-

Firstly we have to convert velocity of train from Km/hr to m/s

→ 36 Km/hr = 36/3.6 = 10 m/s

→ 72 Km/hr = 72/3.6 = 20 m/s

Acceleration of the train :-

$\large \red \bigstar \: \boxed{ \green{\bf Acceleration = \frac{v - u}{t} }}$

$\longmapsto \sf a = \frac{20 - 10}{10}$

$\longmapsto \sf a = \frac{10}{10}$

$\longmapsto \sf a = 1 \: {ms}^{ - 2}$