Question

a train accelerates uniformly from rest to a velocity of 180km/h in half minute. find the distance covered by it in this time guyz pls answer urgent​

Answer 1

Answer:

750m

Explanation:

INITIAL VELOCITY OF TRAIN(u): 0

FINAL VELOCITY (v) : 180 km/h

ON CONVERTING IT TO m/s:

$180 \times \frac{5}{18} = 50m {s}^{ - 1}$

TIME TAKEN(t) : 1/2 minute

1/2 MINUTE = 30 sec

ACCELERATION =

$\frac{v - u}{t} = \frac{50 - 0}{ 30 } = \frac{5}{3} m {s}^{ - 2}$

WE KNOW THAT,

$s = ut + \frac{1}{2} a {t}^{2}$

DISTANCE COVERED IN HALFMINUTE(s):

$0.30 + \frac{1}{2} \times \frac{5}{3} \times {30}^{2} = 750m$

ANSWER : 750m