Question

A train acceleration at 9 m/s squar for 5s .if its initial velocity is 5m/s .what its final velocity ?

Answer 1

Answer:

$\green { \underline {\large{ \boxed {\sf \: final \: velocity \: \: v = 50 \: m {s}^{ - 1} }}}}$

Explanation:

Given,

$\sf \bigstar \: initial \: velocity \: \: u = 5 \: m {s}^{ - 1} \\ \\ \sf \bigstar \: acceleration \: \: a = 9 \: m {s}^{ - 2} \\ \\ \sf \bigstar \: time \: \: t = 5 \: s \\ \\ \pink {\large \bold {\sf \bigstar \: final \: velocity \: \: \: v = to \: find}}$

Formula:

$\huge \: \orange {\bf \: v = u + at }$

Solution :

$\huge \: { \sf v \: = 5 + 9 \times 5} \\ \sf \huge \: \: \: \: \: = 5 + 45 \\ \sf \huge \: \: \: \: \: = 50 \: m {s}^{ - 1}$

$\green{ \boxed {\therefore \sf \: final \: velocity \: \: v = 50 \: m {s}^{ - 1} }}$