A train acceleration from 36 km/h to 54km/h in 10 second.
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Answer:
What I have to find out? tell me
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Explanation:
Here, u= 36 km/h
v= 54 km/h
t = 10 s
Using,
v = u + at
54 = 36 + a × 10
54 - 36 = 10a
18 / 10 = a
Hence, Acceleration is 1.8 km/h^2 Or 0.5 m/s^2
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