a train acceleration from 36 km|hr to 54 km|hrin 10 second find1(acceleration)
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Hey mate
Here is your answer,
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initial velocity of the train = u = 36km/hr = 36×(5/18) m/s = 10 m/s
final velocity = v = 54km/hr = 54×(5/18)m/s = 15 m/s
time = t = 10 sec
as we know acceleration = difference in velocity / time
= (v - u) / t
= (15 - 10)/ 10
= 5/10
= 0.5 m/s²
Hence the acceleration of the train is 0.5 m/s².
★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆
Hope this helps!
Thank you
Sneha
Here is your answer,
★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆
initial velocity of the train = u = 36km/hr = 36×(5/18) m/s = 10 m/s
final velocity = v = 54km/hr = 54×(5/18)m/s = 15 m/s
time = t = 10 sec
as we know acceleration = difference in velocity / time
= (v - u) / t
= (15 - 10)/ 10
= 5/10
= 0.5 m/s²
Hence the acceleration of the train is 0.5 m/s².
★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆★ ☆
Hope this helps!
Thank you
Sneha
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