Question

a train acceralates From 36km/h to 54km/h in 10 sec calculate the acceleration and the distance travelled by train​

Answer 1

Explanation:

Initial speed u = 36 km/h = 36 x 1000/3600 m/s = 10 m/s

Final speed v = 54 km/h = 54 x 1000/3600 m/s = 15 m/s

Time t = 10 s

Acceleration a = (v - u)/t = (15 - 10)/10 = 5/10 = 0.5 m/s2.

Distance travelled  S = ut + ½ at2

                                    = 10 x 10 + ½ x 0.5 x 10 x 10     m

                                    = 100 + 25 = 125 m

Hope it helps you.