Question

a train acclarates at a rate of 5 m/s how long dose it take to reach its top velocity of 90 km / h starting from rest .​

Answer 1

90km/hr can be written as 25m/s

V=u+at

V=0+at

V=at

25=5t

t=5s

Hence it will take 5 seconds

Answer 2

Answer:

Explanation:

Given :

• Initial velocity, u= 0m/s    ( Starts from rest)

• Final velocity, v= 90km/h = 90 × $\dfrac{5}{18}$ = 25m/s

• Acceleration, a= $\bold{ 5 m/s^{2} }$

To find:

Time taken to reach its top velocity= ?

$\boxed{\boxed{\bold{Solution:}}}$

According to the equation of motion :

v = u + at

⇒25= 0 + 5 × t

⇒25= 5t

⇒25÷ 5 = t

⇒$\boxed{\boxed{\bold{t = 5 seconds}}}$

∴Time taken to reach its top velocity= $\boxed{\bold{5seconds}}$

For Information:

To find the distance travelled by the train in 5 second : ?

$\bold{S= ut + \dfrac{1}{2} at^{2} }$

⇒S= 0 × 5 + $\dfrac{1}{2}$ × 5 × 5 × 5

⇒S= 0 + 312.5

⇒S =$\boxed{ \bold{312.5m }}$

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