Question

A train
acelerated from 10 km/her to 40 km/h
in a 2 minutes. how much distance would it
an this period
​

Answer 1

$u = 10 \: km {}^{ - 1} = 2.7 \: ms {}^{ - 1}$

$v = 40 \: km {}^{ - 1} = 11.1 \: \: ms {}^{ - 1}$

$t = 2 \: minutes = 120 \: sec$

$a = ?$

$a = \frac{v - u}{t}$

$a = \frac{11.1 - 2.7}{120}$

$\huge\pink{\boxed{\purple{a = 0.07 \: ms {}^{ - 2}}}}$

For Calculating Distance,

$\huge\pink{s = ut + \frac{1}{2} at {}^{2} }$

$\large{s = 2.7 \times 120 + \frac{1}{2} \times 0.07 \times 120 \times 120}$

$\large{s = 324 + 504}$

$\huge\green{\boxed{\purple{s = 828 \: meter}}}$

$\huge\pink{\underline{\underline{\mathbb{\orange{BrAInLIesT}}}}}$