A train after covering 1/4 of its total distance decreases its speed of 1/3 of its usual speed and reach destination 1 hour 20 minutes late. Find usual time take by the train to cover complete distance.
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Answer: Train proceeds at 3/4 S where S is his usual speed means 1/4 decrease in the speed which will lead to 1/3 increase in the time.
[ As S *T = D, Speed is inversely proportional to time when distance is constant].
Now, the main difference come in those 24 km and the change in difference of time = 35 - 25 = 10 m
= 1 / 3 *T = 10 where T is the time required to cover the distance of (50 - 74) = 24 km
T = 30 min = 0.5 hours
Speed of the train = 24 / (0.5) = 48 km\ph
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