a train after travelling 50 km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late. Had the accident occurred 24 km further, it would have reached the destination only 25 minutes late. Find the total distance of travelling.
Answers
Answer:
Step-by-step explanation:
Let the two endpoints between which this train is running be A and B. Also suppose that accident occurs at C which is at a distance of 50km from A. thus we have
A---------50km----------C----------------------------B 1)
Time taken to travel the distance after the accident i.e. CB is 35 minutes more than the usual time.
Now, if the accident were to occur at 24 km farther, then the train would have reached only 25 minutes late. i.e.
A--------50 km----------C---------24--------D---------------B 2)
If we look at the situation depicted in 1) and 2) we will see that 10-minute difference in time is occurring because of this 24 Km. which is traveled by its usual speed (=x) in the later case. Thus we have,
24⋅43x−24x=1060
32x−24x=16
Solving this we get x = 48 km/h. Regards!
you can find distance from its speed ..hope it will be helpful ..please mark as brainlist;...
Answer:
Step-by-step explanation:Train proceeds at 3/4 S where S is his usual speed means 1/4 decrease in the speed which will lead to 1/3 increase in the time.
[ As S *T = D, Speed is inversely proportional to time when distance is constant].
Now, the main difference come in those 24 km and the change in difference of time = 35 - 25 = 10 m
= 1 / 3 *T = 10 where T is the time required to cover the distance of (50 - 74) = 24 km
T = 30 min = 0.5 hours
Speed of the train = 24 / (0.5) = 48 kmph