A train, an hour after starting, meet with an accident which delays it for half an hour and after this, it proceeds at 3/4th of its former rate and arrives 3.5hrs late. Had the accident happened 90 km farther along the line, it would hav arrived only 3 hour late. The length of trip in km was..?
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Normal time be x for remaining distance, but time taken = 4x/3
Difference in time = (1+1/2+4x/3)−(1+x)=72
x=9
2nd case of going further 90 km which lessens the difference by 1/2
If it loses 90 km in 1/2 hr.
Total difference was 3 + 1/2 out of which 1/2 was for repair
Difference in travelling is 3+1/2-1/2=3 hrs
It will lose 3 hrs in 90 x 6=540 km
Now it travelled for 10 hr hours, which is 1 hr + 540 km
So 540 in 9hr
So 60 km per hour
Total distance = 540+60=600km
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