A train and John's car leave the same place at the same time. Speed of the train is 80 mph.
Speed of car is 60% of the speed of the train. The train takes 15 minutes each to cross first
three stations which are spaced at equal distance. What distance will be traveled by the car,
when the train leaves the third station?
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Step-by-step explanation:
HERE'S YOUR ANSWER
We live in a world defined by the pace of change, and whilst the velocity of that change has not always impacted upon our political in
x= 3y + 4z - 5
therefore
y - 1 = z
sin(x-y)= sinxcosy- cosxsiny
stitutx= 3y + 4z - 5
therefore
y - 1 = z
sin(x-y)= sinxcosy- cosxsiny
HOPE IT HELPS YOU MARK IT BRAINLIEST PLEASE
HOPE IT HELPS YOU MARK IT BRAINLIEST PLEASE
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