Math, asked by uday4044, 1 year ago

A train approaches a tunnel ab. inside the tunnel is a cat located at a point that is 3 8 of the distance ab measured from the entrance
a. when the train whistles the cat runs. if the cat moves to the entrance of the tunnel a, the train catches the cat exactly at the entrance. if the cat moves to the exit b, the train catches the cat at exactly the exit. the speed of the train is greater than the speed of the cat by what order?

Answers

Answered by Fatimakincsem
5

The ratio between the speed of the train and the speed of the cat is 4:1

Step-by-step explanation:

  • Let' say the train is at a distance y from point A.
  • Let AB be the length of the tunnel which is equal to 8 x.
  • Thus, the cat is at distance 3 x from point A.

Hence, the ratio of the speeds of   the cat and the train will be equal to the ratio of the distances traveled by them.

Now the  Required ratio is given below.

y/3x = (y +8x)/5x

5x . y/3x = y + 8x

5y /3 = y +8x

5y = 3y + 24 x

2y = 24 x

y = 12x

Therefore, ratio of the speed = y/3x = 12x/3x = 4 : 1.

Hence the ratio between the speed of the train and the speed of the cat is 4:1

Also learn more

A train is moving with a velocity 120 kmh how much distance does cover in 30 minutes​ ?

https://brainly.in/question/12874542

Similar questions