Question

A train attains the velocity of 90 km/h in 10 seconds starting from rest. Find the acceleration of

train.​

Answer 1

Answer:

Explanation:

velocity = v = 90 km/hr

time taken = t = 10 seconds

acceleration = a = v/t

= 90 \ 10

= 9 km/hr or 9m/s

Answer 2

Answer :

• The acceleration of the train is 2.5m/s^2

Explanation :

Given ,

• The final velocity attained by the body is 90km/h

Changing 90km/h to m/s

$90 \: kmph \: = 90 \times 1000 \times \dfrac{1}{3600} mps$

$90 \: kmph \: = 90 \times 10 \times \dfrac{1}{36} mps$

$90 \: kmph \: = \dfrac{900}{36} mps$

$90 \: kmph \: = 25mps$

Therefore, the final velocity of the body 25m/s

• The body started from rest, therefore it's initial velocity is 0.

• Time taken by it is 10sec

$acceleration \: = \dfrac{v - u}{t}$

here, v = 25m/s , u = 0 m/s , t = 10sec

$\implies \: a = \dfrac{25 - 0}{10} m/ {s}^{2}$

$\implies \: a = 2.5 \: \: m/ {s}^{2}$

Therefore, the value of acceleration is 2.5m/s^2