Question

A train brakes from 60m/s to a stop over a distance of 90m. Find the acceleration

Answer 1

Answer:

-20m/s^2

Step-by-step explanation:

u=60m/s

v=0m/s

s=90m

a=?

2as=v^2 - u^2

2xax90=0^2 - (60)^2

180a= -3600

a= -3600/180

= -20m/s^2

Therefore acceleration is 20m/s^2 in the opposite direction of motion of the train

Answer 2

Step-by-step explanation:

A train brakes from 60m/s to a stop over a distance of 90m. Find the acceleration

answer is -20m/s²