Question

A train can.Cover a distance in 50.Min if it runs at a speed of 48kmph on an average .The sleed at which the train must run to reduce the time of journey to.40min will be

Answer 1

Speed = distance / time
In first case ,
48kmph = dist / (5/6hr)
dist = 40 km

now as a distance is of 40km
so now in second case

speed = 40km /(4/6hr)
speed = 60 kmph