Question

A train consists of 18 carriages .There are 700 passengers travelling on the train .In any block of 5 adjacent carriages there are 199 passengers in total .How many passengers are there in middle two carriages

Answer 1

Answer:

96

Step-by-step explanation:

Step1

C1+C2+C3+C4+C5+C6+C7+C8+C9+C10+C11+C12+C13+C14+C15+C16+C17+C18= 700 passenger

Step2

1+2+3+4+5 = 199 passenger

14+15+16+17+18= 199 passenger

Step3

6+7+8+9+10+11+12+13=700–199–199=302

Step 5

Middle carriage =9+10

Hence

6+7+8+9+10 = 199

9+10+11+12+13=199

Let carriages 9+10= X

Step 6

6+7+8 +X+11+12+13=302

6+7+8+X= 199

Hence

199+c11+c12+c13=302

C11+C12+C13= 302–199=103

Hence C9+C10= ( C10+C11+C12+C13+C14)- (C11+C12+C13)= 199–103=96

ANSWER

The carriages both together will have 96 passengers.

There is catch here

If we assign C9 = Y passenger

& Then C10 = 96 - Y passenger

Hence to get 199 passengers in 5 adjacent carriages

The following contions should be satisfied

C4= y

C5= 96 -Y

C9= y

C10= 96-y

C14= y

C15= 96–Y

THANKS

Answer 2

Answer:

first anser is right