A train cover a distance of 400 km in 5 hrs 40 min. In between the first and last stop it halts in for 5 min in four station. what is the average speed of the train?
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Answer:
56.25 km/hr.
Step-by-step explanation:
Let the speed in return journey be x km/hr.
Then speed in onward journey =100125x=(45x) km/hr.
Average speed =45x+x2×45x×x=910x km/hr.
∴ (800×10x9)=16
x=16×10800×9=45.
Speed in onward journey =(45×45) km/hr =56.25 km/hr.
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