A train covered a certain distance at a uniform speed if the train would have 10 km/hr faster it would have taken 2 hours less than the scheduled time and if the train were
Slower by 10 km/hr it would have taken 3 hours more than the scheduled time find the distance covered by the train
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Let the actual speed of the train be x km/hr and actual time taken y hr. Distance = Speed × Time=xy km
According to the given condition, we havE
xy=(x+10)(y-2)
xy=xy-2x+10y-20
=>10y-2x=20 .......(1)
and
xy=(x-10)(y+3)
xy-10y-30+3x=30
=>-10y+3x=30 ........(2)
solving (1( and (2), we get,
x=50
y=12
Hence, the distance covered by the train=xy
=12x50
=600km
Step-by-step explanation:
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