A train covered a certain distance at a uniform speed. If the train would have been 10km/h faster, it would have taken 2 hours less than the scheduled time. And;if the train were slower by 10km/h; it would have taken 3 hours more than the scheduled time. Find the distance covered by the train.
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Answer:
let distance be=x
let the speed be=y
(x/y) is the normal time taken
(x/y+10) is the new time
x/y+10-(x+y)=2
now if speed is 10km less
(x/y)-(x/y-10 )=3
calculating we get
y=50km/hr
x=600km/hr
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