Question

a train covered a certain distance at a uniform speed.if The train had been 30 km/h faster,it would have taken 2 hour less than the schedule time. If the train were slow by 15 km/ h ,it would have taken 2 hour more than the schedule time.find The length of the journey. plz solve this question withall steps​

Answer 1

Answer:

October 15, 2019

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Sara Sanyal

VIDEO EXPLANATION

ANSWER

Let the speed of the train be xkm/h and the time taken by train to travel the given distance be t hours and the distance to travel be dkm. We know that,

⇒Speed=

Time

Distance

⇒x=

t

d

∴d=xt.......(i)

Case 1

⇒(x+10)×(t−2)=d

⇒xt+10t−2x−20=d

⇒d+10t−2x−20=d

⇒−2x+10t=20...... (ii)

Case 2

⇒(x−10)×(t+3)=d

⇒xt−10t+3x−30=d

⇒d−10t+3x−30=d

⇒3x−10t=30......... (iii)

Adding equations (ii) and (iii), we gets

⇒x=50

Substitute the value of x in (ii) we gets

⇒(−2)×(50)+10t=20

⇒−100+10t=20

⇒10t=120

⇒t=12 hours

Substitue the value of t and x in equation (i), we gets

Distance to travel =d=xt

⇒d=12×50=600Km

Hence, the distance covered by the train is 600km.

Step-by-step explanation:

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Answer 2

Let the speed of the train = x km/h .

The time taken by train to travel the given distance = t hours .

And the distance to travel = d km .

km .We know that,

$speed = \frac{distance}{time}$

=>x = d/t

=>d= xt

Case: 1

=> (x+10)×(t−2) = d

=> xt+10t−2x−20 = d

=> d+10t−2x−20 = d

=> −2x+10t = 20............. (i)

Case: 2

=> (x−10)×(t+3)=d

=> xt−10t+3x−30=d

=> d−10t+3x−30=d

=> 3x−10t=30......... (ii)

Adding equations (i) and (ii)

we get,

=> x=50

Putting the value of x in eq(i)

=> (−2)×(50)+10t = 20

=> −100+10t = 20

=> 10t = 120

=> t = 12 hours

We get the value of x and t

Now,

Distance to travel = d =xt

=> d = 12×50 = 600Km

Hope it will help you ✌️