Question

A train covered a certain distance at a uniform
speed. If the train would have been 12 km/h
faster, it would have taken 2 hours 40 minutes less
time than the schedule time and if the train were
slower by 12 km/h, it would have taken 4 hours
more than the schedule time. Find the length of
the journey and the speed of the train.

Answer 1

Answer:

let the distance travelled by train be d km

speed of the train be s km/ hr

and the total time taken be t hrs.

so s= d/t

Or d= s*t

now d/ s+12= t- 160/60

d/s+12= 3t-8/3

d= (3t-8) (s+12) /3.................(1)

d/s-12=t+4

d=(t+4) (s-12) ........................ (2)

equating equation (1) and (2) :

(3t-8) (s+12) /3=(t+4) (s-12)

s=18t+12/5

d=s*t= t(18t+12/5)

d=18t^2+12t/5

putting the value of d and s in equation (1) :

t=16 hrs

now s= 60 km/ hr

d= 960km