Question

A train covered a certain distance at a uniform
speed. If the train would have been 12 km/h
faster, it would have taken 2 hours 40 minutes less
time than the schedule time and if the train were
slower by 12 km/h, it would have taken 4 hours
more than the schedule time. Find the length of
the journey and the speed of the train.

Answer 1

Answer:

Let the time taken be t,

and speed be x.

i.e., distance = xt

In case 1

 time = t1

time = xt / x + 10                    (time = distance / speed)

xt / x + 10 = t - 2

xt = (t - 2 ) (x + 10)

xt = xt + 10t - 2x - 20

xt and xt get cancelled

10t - 2x - 20 = 0                   ... equation 1

In case 2

 t2 = xt / x- 10

xt / x - 10 = t + 3

xt = (t + 3) (x - 10)

 xt = xt - 10t + 3x - 30

 xt and xt get cancelled

-10t + 3x - 30 = 0                  .... equation 2

now u can solve this by using any 1 method i.e, substitution, elimination or cross-multiplication

refer this and solve this answer

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