Question

A train covered a certain distance at a uniform speed. If the train would have been 10 km/h faster, it would have been taken 2 hours less than the scheduled time. And, if the train were slower by 10 km/h; it would have taken 3 hours more than the scheduled time. Find the distance covered by train.

Answer 1

HELLO DEAR,

let the speed of the train be x km/hr
time taken be( y) hrs

and distance be (x.y )km

given that:-

conditions(1)

If the train were slower by 10 km/hr, it would have taken 3 hours more than the scheduled time

=> (x - 10) (y +  3) = xy

=> xy +3x -10y -30=xy

=> 3x – 10y - 30 = 0

=> 3x – 10y = 30 ----------------(1)

now ,

conditions(1)

If the train would have been 10 km/hr faster, it would have taken 2 hours less than the scheduled time.

=> (x + 10) (y - 2) = xy

=> xy -2x +10y -20=xy

=> -2x + 10y = 20

=> x – 5y = -10 ---------------- (2)

from (1) and (2)
multiply by 2 in-- Equation(2)
we get,

3x – 10y = 30
2x – 10y= -20
(-) (+) (+)
_____________
x=50 put in --(1)

we get,

50 - 5y= -10

5y = 50+10

y=60/5

y = 12

the distance of the journey = 50 × 12 = 600 km.

I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

Hello.....

Here is the solution for your question....

Thank you so much....