Question

A train covered a certain distance at a uniform speed. If the train had been 5 kmph faster, it would have taken 3 hours less than the scheduled time And, if the train were slower by 4 kmph, it would have taken 3 hours more than the scheduled time. Find the length of the journey no
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Answer 1

Z\huge\fcolorbox{black}{lime}{AnsweR:}AnsweR:

\large\boxed{\mathfrak{2^9*(\frac{1}{3})^1^7 }}

\bold{ExplantioN:}ExplantioN:

\large\boxed{\mathfrak{\frac{(-2)^2^4*(-3)^1^7*(8)^-^9}{(12)^1^6*(27)^6} }}

\large\boxed{\mathfrak{\frac{(-2^2^4)*(-3)^1^7*(8)^-^9}{(12)^1^6*(3^3)^6} }}

\begin{gathered}\large\boxed{\mathfrak{\frac{(-2^2^4)*(-3)^1^7*(8)^-^9}{(12)^1^6*(3)^1^8} }}\\\\\\\large\boxed{\mathfrak{\frac{(-1*2)^2^4*(-1*3)^1^7*2^-^2^7}{2^1^6*2^1^6*3^1^6*3^1^8} }}\end{gathered}

\large\boxed{\mathfrak{\frac{-1^2^4^+^1^7*2^2^4^+^1^7*3^1^7}{2^3^2*3^3^4} }}

\large\boxed{\mathfrak{-1^4^1*2^9*3^-^1^7}}

\large\boxed{\mathfrak{2^9*(\frac{1}{3})^1^7 }}      .

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