Question

A train covered a certain distance at a uniform speed. if the train would have been 6km/hr faster, it would have taken 4 hours less than the scheduled time and if the train was the slower by 6km/hr, it would have taken 6 hours more than the scheduled time. find the length of the journey .

Answer 1

hey

Let t be the usual time taken by the train to cover the distance
Let d be the distance, s be the usual speed

Usual time taken => d/s = t => d=ts
d/(s+6) = t-4
ts/(s+6) = t-4
ts = ts+6t-4s-24 
6t - 4s - 24 = 0 --> (1)

d/(s-6) = t+6
ts = ts-6t+6s-36
-6t + 6s - 36=0 --->(2)

Solving (1) nd (2), v get

s = 30 km/h
t = 24 hrs
d = t * s
d = 30 ×24 = 720 km