Question

a train covered A certain distance at a uniform speed if the train would have been 6 km per hour faster it would have taken 4 hours less than the scheduled time and if the train was lower by 6 km per hour it would have taken 6 hours more than the scheduled time find the distance of the journey

Answer 1

Let t be the usual time taken by the train to cover the distance
Let d be the distance, s be the usual speed

Usual time taken => d/s = t => d=ts
d/(s+6) = t-4
ts/(s+6) = t-4
ts = ts+6t-4s-24 
6t - 4s - 24 = 0 --> (1)

d/(s-6) = t+6
ts = ts-6t+6s-36
-6t + 6s - 36=0 --->(2)

Solving (1) nd (2), v get

s = 30 km/h
t = 24 hrs
d = t * s
d = 30 * 24 =720 km

or
From formula 
D=st
given
D=(s+6)(t-4)=st-4s+6t-24.......>1
D=(s-6)(t+6)=st+6s-6t-36)......>2

from 1&2 
-4s+6t=24
6s-6t=36 .....>3

on solving 
2s=60 ==> s=30 km/h
(3)==> 6(30)-6t=36
t= 24 h
.
. . D=30(24) = 720 km


Ans: D= 720 km

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Answer 2

Answer:

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