Question

A train covered a certain distance at a uniform speed. If the train would have been 6 km/hr faster, it would have taken 4 hours less than the scheduled time and if the train was slower by 6 km/hr, it would have taken 6 hours more than the scheduled time. Find the length of the journey.

Answer 1

solution:-

let speed of train = X km/h

Let time taken = y hrs.

Distance = xy km

step 1st

(x + 6) (y - 4) = xy

xy - 4x + 6y - 24 = xy

6y - 4x = 24 ---------------------(i)

step 2nd

(x - 6) (y + 6) = xy

xy + 6x - 6y - 36 = xy

6x - 6y = 36 ----------------------(ii)

from equation (i) and (ii)

6y - 4x + 6x - 6y = 24 + 36
2x = 60
x = 30.

from equation (ii)

6(30) - 6y = 36

180 - 6y = 36

-6y = - 144

y = 24.

So, speed = 30 km/hr.

Time = 24 hrs.

Distance = 24 × 30

= >720 km.

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@GsuravSaxens01

Answer 2

Answer:

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