Math, asked by aaravshrivastwa, 11 months ago

A train covered a certain distance at an uniform speed. If the train would have been 10 Km/h faster it would have taken 2 hours less than the scheduled time but if the train were 10 Km/h slower then it would have taken 3 hours more than the scheduled time. Find the distance covered by the Train.


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Answers

Answered by anjalisain123
1

Answer:Let the speed of the train be xkm/h and the time taken by train to travel the given distance be t hours and the distance to travel be dkm. We know that,

⇒Speed=

Time

Distance

⇒x=

t

d

∴d=xt.......(i)

Case 1

⇒(x+10)×(t−2)=d

⇒xt+10t−2x−20=d

⇒d+10t−2x−20=d

⇒$$− 2x + 10t = 20$$...... (ii)

Case 2

⇒(x−10)×(t+3)=d

⇒xt−10t+3x−30=d

⇒d−10t+3x−30=d

⇒$$3x − 10t = 30$$......... (iii)

Adding equations (ii) and (iii), we gets

⇒x=50

Substitute the value of x in (ii) we gets

$$\Rightarrow (−2) \times (50) + 10t = 20$$

$$\Rightarrow −100 + 10t = 20$$

⇒10t=120

⇒t=12 hours

Substitue the value of t and x in equation (i), we gets

Distance to travel =d=xt

⇒d=12×50=600Km

Hence, the distance covered by the train is 600km.

Answered by Anonymous
2

Let the time taken be t,

and speed be x.

i.e., distance = xt

In case 1

time = t1

time = xt / x + 10 (time = distance / speed)

xt / x + 10 = t - 2

xt = (t - 2 ) (x + 10)

xt = xt + 10t - 2x - 20

xt and xt get cancelled

10t - 2x - 20 = 0 ... equation 1

In case 2

t2 = xt / x- 10

xt / x - 10 = t + 3

xt = (t + 3) (x - 10)

xt = xt - 10t + 3x - 30

xt and xt get cancelled

-10t + 3x - 30 = 0 .... equation 2

now u can solve this by using any 1 method i.e, substitution, elimination or cross-multiplication.

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