A train covered a certain distance at uniform speed. If the speed of the train would have been 15km/h more, it would have taken 1 hour less than the scheduled time. If the speed of the train would have been 15 km/h less, it would have taken 1.5 hours more than the scheduled time. Find the distance covered by the train.
Answers
Answer:
Let the speed of the train be xkm/h and the time taken by train to travel the given distance be t hours and the distance to travel be dkm. We know that,
⇒Speed=
Time
Distance
⇒x=
t
d
∴d=xt
Case 1
⇒(x+10)×(t−2)=d
⇒xt+10t−2x−20=d
⇒d+10t−2x−20=d
⇒−2x+10t=20
Case 2
⇒(x−10)×(t+3)=d
⇒xt−10t+3x−30=d
⇒d−10t+3x−30=d
⇒3x−10t=30
Adding equations (ii) and (iii), we gets
⇒x=50
Substitute the value of x in (ii) we gets
⇒(−2)×(50)+10t=20
⇒−100+10t=20
⇒10t=120
⇒t=12 hours
Substitue the value of t and x in equation (i), we gets
Distance to travel =d=xt
⇒d=12×50=600Km
Hence, the distance covered by the train is 600km.
Answer:
A train covered a certain distance at a uniform speed. If the train would have been 10 km/h faster, it would have taken 2 hours less than the scheduled time. And, if the train were slower by 10 km/h; it would have taken 3 hours more than the scheduled time. Find the distance covered by the train