A train covered A certain distance at uniform speed if the train would have been 6 kilometre per hour slower it would have taken 12 hour more than the scheduled time and if the train were 6km/h faster it would have taken 8 hour less than the schedule time find the distance covered by train please answer it urgent
sonam95:
Please solve it urgent
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here is your answer by Sujeet yaduvanshi,
Given that,
a train covered A distance at uniform motion,
distance of journey=xy
Now, we can follow on..
A/q.
let to be original speed x
let to be time taken y
Case 1.
(x-6)(y+12)=xy
xy-6y+12x-72=xy
-6y+12x=72....
12x-6y=72 _____(3)
Case 2..
(x+6)(y-8)=xy
xy+6y-8x-48=xy
-8x+6y=48____(4)
Now solving the equation by elimination method,for equation 3 and 4
12x-6y=72. *-8
-8x+6y=48. *12
-96x+48y=-576
-96x+72y=+576
_____________
24y=1152
y=1152/24=48
Again,
12x-6y=72
12x-6(48)=72
12x-288=72
12x=72+288
12x=360
x=360/12
x=30
Now,
Distance=Time* speed
Distance=30*48
Distance=1440km
that's all,
Dear Sonam...
Answer by Sujeet yaduvanshi
Given that,
a train covered A distance at uniform motion,
distance of journey=xy
Now, we can follow on..
A/q.
let to be original speed x
let to be time taken y
Case 1.
(x-6)(y+12)=xy
xy-6y+12x-72=xy
-6y+12x=72....
12x-6y=72 _____(3)
Case 2..
(x+6)(y-8)=xy
xy+6y-8x-48=xy
-8x+6y=48____(4)
Now solving the equation by elimination method,for equation 3 and 4
12x-6y=72. *-8
-8x+6y=48. *12
-96x+48y=-576
-96x+72y=+576
_____________
24y=1152
y=1152/24=48
Again,
12x-6y=72
12x-6(48)=72
12x-288=72
12x=72+288
12x=360
x=360/12
x=30
Now,
Distance=Time* speed
Distance=30*48
Distance=1440km
that's all,
Dear Sonam...
Answer by Sujeet yaduvanshi
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