A train covered a certain distance at uniform speed is the train would have been 10 km faster it would have take 2 hour less than the scheduled time and if the train was lower by 10 km it would have taken 3 hours more than the scheduled time find the distance covered by train
Answers
Answered by
0
Let the time taken be t,
and speed be x.
i.e., distance = xt
In case 1
time = t1
time = xt / x + 10 (time = distance / speed)
xt / x + 10 = t - 2
xt = (t - 2 ) (x + 10)
xt = xt + 10t - 2x - 20
xt and xt get cancelled
10t - 2x - 20 = 0 ... equation 1
In case 2
t2 = xt / x- 10
xt / x - 10 = t + 3
xt = (t + 3) (x - 10)
xt = xt - 10t + 3x - 30
xt and xt get cancelled
-10t + 3x - 30 = 0 .... equation 2
now u can solve this by using any 1 method i.e, substitution, elimination or cross-multiplication.
and speed be x.
i.e., distance = xt
In case 1
time = t1
time = xt / x + 10 (time = distance / speed)
xt / x + 10 = t - 2
xt = (t - 2 ) (x + 10)
xt = xt + 10t - 2x - 20
xt and xt get cancelled
10t - 2x - 20 = 0 ... equation 1
In case 2
t2 = xt / x- 10
xt / x - 10 = t + 3
xt = (t + 3) (x - 10)
xt = xt - 10t + 3x - 30
xt and xt get cancelled
-10t + 3x - 30 = 0 .... equation 2
now u can solve this by using any 1 method i.e, substitution, elimination or cross-multiplication.
Similar questions