Question

a train covered a distance at a uniform speed if the train would have been 6 km per hour fasted it would have taken 4 hours less than the scheduled time and if the train was given by 6 km per hour it would have taken 6 for more than the scheduled time find the length of the journey

Answer 1

let x be usual speed of train

t be time taken to cover the distance at speed x

let d be distance

so , d = xt ----- 1

according to first condition ,

if x+6 then t-4

( x+6 ) ( t-4 ) = d ----- 2

from 1 and 2

( x+6 ) ( t-4 ) = xt

xt - 4x + 6t - 24 = xt

- 4x + 6t = 24 -------- 3


according to second condition ,

if x- 6 then t + 6

( x- 6 ) ( t- 6 ) = d -----4

from 1 and 4

( x-6 ) ( t + 6 ) = xt

xt + 6x - 6t - 36 = xt

6x - 6t = 36 -------- 5


adding 3 and 5 we get
.
2x = 60

x =30 km/hr

putting this value in eq 3

-120 + 6t = 24

6t = 144

t = 24 hours


so distance d = 30 × 24 = 720 km

Answer 2

Answer:

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