A train covers 3/7 of the total distance in the 1st hour of journey and covers 2/5 of the journey in 2nd hour. How much of the journey is left?
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Answer:
6/35
Step-by-step explanation:
- let the distance be x
- given:
- distance covered in 1st hour = 3/7 × total distance covered = 3/7 × x = 3x/7
- distance covered in 2nd hour = 2/5 × total distance covered = 2/5 × x = 2x/5
3. Total distance covered = 3x/7 + 2x/5
=(15x+14x) /35
=29x/35
4. Distance left = x - 29x/35
= (35x-29x) /35
= 6x/35 = 6/35 of x = 6/35 of total distance
5. Thus, 6/35 of total journey is left
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