Question

 A train covers a distance in 50 min, if it runs at a speed of 48kmph on an average. The speed at which the train must run to reduce the time of journey to 40min will be 

A.    45 min


B.    60 min


C.    55 min


D.    70 min

​

Answer 1

Answer : B.

Time = 50/60 hr = 5/6hr

Speed = 48mph

distance = S*T = 48 * 5/6 = 40km

time = 40/60hr = 2/3hr

New speed = 40* 3/2 kmph = 60kmph

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Answer 2

Answer:

distance=speed×time=5/6×48=40km

then required speed=distance/time

=40÷4/6=60km