Question

a train covers a distance in 50 minutes, if it runs at a speed of 48 km per hour on an average. find the speed at which the train must run to reduce the time of journey to 40 minutes


I need answer in decimal​

Answer 1

Answer:

Speed (S) = 48 kmph. Time (T) = 50 min = 50/60 = 5/6 hours. New Speed = s (let). New Time (t) = 40 min = 40/60 = 2/3 hours.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

time=50min

average speed=48km/hrs

$\color{purple} \boxed{Distance=speed×time}$

Distance =50min×48km/hrs

$50min \times \frac{48km}{60min} = 40km$

now let the speed =x

when train travels 40km in 40min

so speed =distance/time

x=40km/40min

=1km/min

=1km÷1/60hrs

=1×60=60km/hrs

is the speed