A train covers a distance of 300 km at a uniform speed. If the speed o
the train is increased by 5 km/hour, it takes 2 hours less in the journey
Find the original speed of the train.
Help me guys please
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Answer:
Let x km/h be the constant speed of train.
Time taken to cover 300km = 300 / x hrs
Increased speed = x + 5
Time taken to cover 300km when speed is increased to 5 km/h = 300 / x + 5
According to question
300 / x - 300 / x + 5 = 2
300( x + 5) - 300x / x(x + 5) = 2
300x + 1500 - 300x / x2 + 5x = 2
2(x2 + 5) = 1500
2x2 + 10 = 1500
2x2 + 10 - 1500 = 0
2x2 + 10 - 1500 = 0
(divide by 2 )
x2 + 5 - 750 = 0
30 x -25 = -750
30 + -25 = 5
x2 + 30x - 25x - 750 = 0
x(x + 30) - 25(x + 30) = 0
(x + 30) (x - 25) = 0
x = -30 ( It is rejected because speed cannot be negative )
So , constant speed be 25 km/hr.
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