Question

a train covers a distance of 670 km in 6 hour 5 minutes if it covers the first 390 km of the journey at 90 km per hour find its speed for the rest of the journey

Answer 1

see joy28.

total distance is 670km
total time is (6+5by60)hr
=(6+1by12)hr
= 73/12 hr






then 1st case .

distance is 390km
speed is 90km/hr

then time will be 390/90
= 13/2 hr.


2nd case for the rest of the journey.


distance will be. 670-390 is 280km


time will be. (73/12) - (13/3) = (73-52)/12 = 7/4 hr

thn speed for the rest of the journey will be distance by time


=>. 280by 7/4
=>. (280 X 4 )/7

=>. 160km/hr(Ans).




hope it helps.

thanks

Answer 2

total distt covrred=670km
total time taken=6hr 5min
1. 390 km
speed=90kmper hr
390/90=13/3hr=3hr and 20 min
rest time left= 6 hr 5 min-3hr 20 min=2hr 45 min
dist left=670km-390km= 280km
speed =dist/time
=280/2.45
8/7m per sec
hope this help u and tap thanks and mark brainliest plzzzz....