Question

A train covers a distance of 880 km at a constant speed. if its speed would be 15 km / hr more, then it would have taken 6 hours less ot cover the same distance. what is the original speed of the train?

Answer 1

$880 \div x - 880 \div 15 - x = 6$
$880(1 \div x) - (1 \div 15 - x) = 6$
$x - 15 + x \div {x}^{2} - 15 x = 880 \times 6$