Question

A train covers a distance of 90 km at a uniform speed. Had the speed been 15 km 1hr more it would have

taken 30 minutes less for the journey . Find the original speed of the train​

Answer 1

Answer:

hey mate here is the answer

Step-by-step explanation:

90/x- 90/x+15 = 1/2

90[x+15-x/x(x+15)]= 1/2

90×15/x²+15x = 1/2= x²+15x= 2700

x²+15x-2700= 0

x²+60x-45x-2700= 0

x(x+60)-45(x+60)= 0

(x+60) (x-45) = 0

x= -60 or 45

ans - hence usual speed of train = 45 km/hr

Answer 2

apun 2-3 minute phele hi spammer bana jab kisi ne apun ka Question pe spam kara !!

samja kya!!