A train covers half of its journey with a speed of 30 metre per second and the other half with the speed of 40 metre per second .Calculate the arc speed of the train during the whole journey.
Answers
Answered by
2
Answer:
ans is 2v1v2/v1+ v2
2400/70=34.2
Attachments:
aniket00715:
explain iy
explain it also
i have attached the image.hope it helps
ohh srry i didn't seen that
Answered by
1
Answer:
We take distance =x speed=d/t1 t1=d/s t1=x/30 speed=d/to t2=d/s t2=x/40 total time = t1+t2
= x/30+x/40
= 7x/120
total distance = x+x
=2x
total speed = to.d/to.t
= 2x/7x/120
=34.28 mper second square
Explanation:
speed = distance/time
Take time for speed 1 as t1 and speed 2 as t2
So, average speed = d/(t1+t2)
speed 1,
30 = d/2t1
t1 = d/2*30 ---------------1
speed 2,
40 = d/2t2
t2 = d/2*40 --------------2
Add 1 and 2 to find average speed,
t1+t2 = d/60 +d/80
t1+t2 = d[1/60 +1/80]
t1+t2 = d *[7/240]
average speed, d/(t1+t2) =240/7 = 34.28 m/s
Attachments:
Similar questions