A train covers the first 30 km of its journey in 20 m, next 50 km in another 20 m and the last 20 km in 10 m. Average speed of the train will be
Answers
Explanation:
\sf \red {\underline{\underline{Given:-}}}
Given:−
A train covers the first 30 km of its journey in 20 minutes.
The next 50 km in another 20 minutes,
The last 20 km in 10 minutes.
\sf \blue{\underline{\underline{To\:Find:-}}}
ToFind:−
The average speed of the train.
\sf \green {\underline{\underline{Solution:-}}}
Solution:−
\boxed{\sf \purple{Average \: \: speed \: = \frac{Total \: \: distance \: }{Total \: \: time} }}
Averagespeed=
Totaltime
Totaldistance
\sf{ \:Total \: distance \: = 30km + 50km + 20km}Totaldistance=30km+50km+20km
\sf{ = 100km}=100km
\sf total \: \: time \: = 20min \: + 20min + 10mintotaltime=20min+20min+10min
\sf = 50 minutes=50minutes
\sf Average \: speed = \dfrac{100}{50}Averagespeed=
50
100
\sf = 2=2
\boxed{ \sf \pink{Average \: speed \: = 2m/s}}
Averagespeed=2m/s
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