Question

A train covers the first 30 km of its journey in 20 minutes,the next 50 km in another 20 minutes,and the last 20 km in 10 minutes.Calculate the average speed of the train?

Answer 1

Explanation:

$\sf \red {\underline{\underline{Given:-}}}$

• A train covers the first 30 km of its journey in 20 minutes.

• The next 50 km in another 20 minutes,

• The last 20 km in 10 minutes.

$\sf \blue{\underline{\underline{To\:Find:-}}}$

• The average speed of the train.

$\sf \green {\underline{\underline{Solution:-}}}$

$\boxed{\sf \purple{Average \: \: speed \: = \frac{Total \: \: distance \: }{Total \: \: time} }}$

$\sf{ \:Total \: distance \: = 30km + 50km + 20km}$

$\sf{ = 100km}$

$\sf total \: \: time \: = 20min \: + 20min + 10min$

$\sf = 50 minutes$

$\sf Average \: speed = \dfrac{100}{50}$

$\sf = 2$

$\boxed{ \sf \pink{Average \: speed \: = 2m/s}}$

Answer 2

Explanation:

\sf \red {\underline{\underline{Given:-}}}

Given:−

A train covers the first 30 km of its journey in 20 minutes.

The next 50 km in another 20 minutes,

The last 20 km in 10 minutes.

\sf \blue{\underline{\underline{To\:Find:-}}}

ToFind:−

The average speed of the train.

\sf \green {\underline{\underline{Solution:-}}}

Solution:−

\boxed{\sf \purple{Average \: \: speed \: = \frac{Total \: \: distance \: }{Total \: \: time} }}

Averagespeed=

Totaltime

Totaldistance

\sf{ \:Total \: distance \: = 30km + 50km + 20km}Totaldistance=30km+50km+20km

\sf{ = 100km}=100km

\sf total \: \: time \: = 20min \: + 20min + 10mintotaltime=20min+20min+10min

\sf = 50 minutes=50minutes

\sf Average \: speed = \dfrac{100}{50}Averagespeed=

50

100

\sf = 2=2

\boxed{ \sf \pink{Average \: speed \: = 2m/s}}

Averagespeed=2m/s