a train cross a person in 24sec. but it cross a 156 m long platform with 20% more speed than previous speed in 33 sec. find the initial speed of train?
Answers
Answered by
1
Answer:
2 m/sec
Step-by-step explanation:
Speed of train =120 kmph
=
18
120×5
=
3
100
m/sec
Let 'x' be the length of platform
Now,
Time taken in crossing
Length of train and platform
=
3
100
⇒
24
320+x
=
3
100
⇒320+x=
3
24×100
⇒320+x=800
⇒x=480 m
∴ Man's speed =
4×60
480
=2 m/sec
Answered by
0
Answer:
Speed of train =120 kmph
=
18
120×5
=
3
100
m/sec
Let 'x' be the length of platform
Now,
Time taken in crossing
Length of train and platform
=
3
100
⇒
24
320+x
=
3
100
⇒320+x=
3
24×100
⇒320+x=800
⇒x=480 m
∴ Man's speed =
4×60
480
=2 m/sec
Step-by-step explanation:
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