a train crosses a platform 90 M long in 30 seconds and a man standing on the platform 15 second find the speed of the train
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Answered by
17
speed of train is 6 second
sunadapriyaSunada:
Process plz
I provided the process... you may see the process in my answer
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Answered by
108
Case 1:
d=(90+x)m
t=30s
s=(90+x)/30
Case 2:
d=x m
t=15 s
s=x/15
x/15=(90+x)/30
x=(90+x)/2
2x=90+x
x=90 m
Length of train =90 m
Speed =x/15 m/s
=90/15m/s
=6 m/s.
# A student of class 10.
#Hope it helps.
# PLZZZZ mark brainliest.
d=(90+x)m
t=30s
s=(90+x)/30
Case 2:
d=x m
t=15 s
s=x/15
x/15=(90+x)/30
x=(90+x)/2
2x=90+x
x=90 m
Length of train =90 m
Speed =x/15 m/s
=90/15m/s
=6 m/s.
# A student of class 10.
#Hope it helps.
# PLZZZZ mark brainliest.
Done
It’s ok
thanks sunandapriya
Same smriti
but pls tell me how we mark brainlist
It’s near comment vote and thank area
some where there
ok thanks
It I did not do this sum I would see hell tomorrow
Thank again
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