Question

a train crosses two bridges which are 215m and 275m long in 15 sec and 18 sec respectively find the speed of train

Answer 1

Answer:

speed of train = total distance ÷ total time

(215 + 275)m ÷ (15 + 18 )sec

= 490m ÷ 33s = 14.84 m/s

Answer 2

The speed of the train is 14.85 m/s.

Given:

A train crosses two bridges which are 215m and 275m long in 15 sec and 18 sec respectively.

To Find:

The speed of the train.

Solution:

To find the speed of the train we will follow the following steps:

As we know,

The speed of the train will be the ratio of the total distance traveled to the total time taken.

Total distance traveled =

$(215 + 275)m = 490m$

Now,

Total time is taken =

$(15 + 18) \: sec = 33sec$

So,

In putting values we get,

$speed = \frac{total \: distance}{total \: time} = \frac{490}{33} = 14.85m {s}^{ - 1}$

Henceforth, the speed of the train is 14.85 m/s.

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