Question

A train first travels for 30min with a velocity of 30kmph and then for 40min with a velocity of 40kmph in the same direction. Calculate the total distance travelled and the average velocity of the train.

Answer 1

the answer is 41.6 kms.
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Answer 2

Answer:

The total distance is 41.6 km and the average velocity is 35 km/h

Explanation:

Given that,

Time in first travel = 30 min

Velocity of first travel = 30 km/h

Time in second travel = 40 min

Velocity of second travel= 40 km/h

The distance covers in first travel

$d =v\times t$

$d = 30\times\dfrac{1}{2}$

$d=15\ km$

The distance covers in second travel

$d =v\times t$

$d = 40\times\dfrac{2}{3}$

$d=26.6\ km$

The total distance is

$D=d_{1}+d_{2}$

$D=15+26.6$

$D = 41.6\ Km$

The average velocity is

$v_{av}=\dfrac{v_{2}+v_{1}}{2}$

$v_{av}=\dfrac{40+30}{2}$

$v_{av}=35\ km/h$

Hence, The total distance is 41.6 km and the average velocity is 35 km/h.