Math, asked by nareshpawar8899, 27 days ago


A train from Station A to Station B covers a distance of 616km at a uniform speed of
112km/hr. It Halts at Station B for 1 hour before starting back. How much time will it
take to complete the journey and reach back to Station A (i.e. from A to B and back)
(a)11 hours (b) 12 hours 45 minutes (c)12 hours (d) 5 hours
30 minutes
A table was sold at 16% loss for 3360.Find the cost price of the table
(a) ₹4000
(b) ₹3392
(c) ₹3600
(d) ₹4296​

Answers

Answered by ananyamishra1977
2

Answer

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Answered by anvi1507
3

mark it as brainliest

Answer:

for the first question: (C) 12hours

and the second question: (A) ₹4000

Step-by-step explanation:

FIRST QUESTION:

Given-

Journey distance s = 616 km

Train speed v = 112 km/hr

Halting time = 1 hr

Solution-

Time taken for A=>B,

t = s / v

t = 616 / 112

t = 5.5 hr

Train halts at station B for 1 hr before returning.

Train will take same time i.e. 5.5 hr to return.

Total journey time = 5.5 + 1 + 5.5 = 12 hr

Total time taken by train will be 12 hr.

SECOND QUESTION:

Let the CP be ₹x.

Then according to the given condition, we have

SP = ₹3360

Loss = 16%

Therefore to find CP,

x × (1 - 16/100) = 3360

x × (0.84) = 3360

or x = 3360/0.84

Therefore, x = ₹4000/-  

Hence, the cost price of the table is ₹4000/-

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