A train from Station A to Station B covers a distance of 616km at a uniform speed of
112km/hr. It Halts at Station B for 1 hour before starting back. How much time will it
take to complete the journey and reach back to Station A (i.e. from A to B and back)
(a)11 hours (b) 12 hours 45 minutes (c)12 hours (d) 5 hours
30 minutes
A table was sold at 16% loss for 3360.Find the cost price of the table
(a) ₹4000
(b) ₹3392
(c) ₹3600
(d) ₹4296
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Answer:
for the first question: (C) 12hours
and the second question: (A) ₹4000
Step-by-step explanation:
FIRST QUESTION:
Given-
Journey distance s = 616 km
Train speed v = 112 km/hr
Halting time = 1 hr
Solution-
Time taken for A=>B,
t = s / v
t = 616 / 112
t = 5.5 hr
Train halts at station B for 1 hr before returning.
Train will take same time i.e. 5.5 hr to return.
Total journey time = 5.5 + 1 + 5.5 = 12 hr
Total time taken by train will be 12 hr.
SECOND QUESTION:
Let the CP be ₹x.
Then according to the given condition, we have
SP = ₹3360
Loss = 16%
Therefore to find CP,
x × (1 - 16/100) = 3360
x × (0.84) = 3360
or x = 3360/0.84
Therefore, x = ₹4000/-
Hence, the cost price of the table is ₹4000/-
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