Question

A TRAIN FROM STATIONARY AND MOVING WITH UNIFORM ACCELERATION ATTAINS A SPEED OF 36km/h in 10 minutes find its acceleration

Answer 1

Answer:

if a train starts from stationary position then initial velocity of train = 0

moving uniform acceleration means constant acceleration .

given ,

final velocity ( V) = 36 km/h = 36× 5/18

= 10m/s

time taken = 10 minutes = 10× 60sec

= 600sec

use kinematics equation ,

V = u + at

10 = 0 + a × 600

a = 10/600 = 1/60 m/s²

a = 0.1667 × 10^-1 m/s² = 1.67 × 10^-2 m/s²

Answer 2

Answer:

Acceleration = change in velocity/ time

Acceleration = 10-0 / 10×60

Acceleration =1/60 m/sec^2