Question

A train full of passengers reaches at the first station where it drops 1/3 of the passengers and takes 280 more. at the second station, it drops one half of the new total and takes twelve more on arriving at the third station.the train is now found to have 248 passengers. find the no of passengers in the beginning? ticka 300

Answer 1

Solution -

Let the no of passengers be x.

At first station, no of passengers = x - x/3 + 280

At second station, no of passengers = 1/2 ( x - x/3 + 280) + 12

At Third station, no of passengers = 248.

Given

248 =  1/2 ( x - x/3 + 280) + 12

 248 = x/2 - x/6 + 140 + 12

248 = 2x/6 + 152

248 - 152 = x/3

96 = x/3

x = 96 * 3

x = 288

Answer - The no of passengers in the beginning are 288 

Answer 2

Step-by-step explanation:

Let the number of passengers be x

At first station, no of passengers =x-x/3=2x/3

At second station, no of passengers = 1/2(x- x/3+280)+12

At the third station no of passengers =248

Given,

248=1/2(x- x/3+280)+12

248=x/2-x/6+140+12

248=2x/6+152

248-152=x/3

96=x/3

x=96×3

x=288